پروژه note در بخش متود get دیتا بیس اینسرت نمیشه

package ir.hjozve.etelaat;

import android.os.Bundle;
import android.support.v7.app.AppCompatActivity;
import android.view.View;
import android.widget.EditText;
import android.widget.TextView;

import com.android.volley.Request;
import com.android.volley.RequestQueue;
import com.android.volley.Response;
import com.android.volley.VolleyError;
import com.android.volley.toolbox.StringRequest;
import com.android.volley.toolbox.Volley;

import java.util.HashMap;
import java.util.Map;

public class Main2Activity extends AppCompatActivity {
    private TextView textView;
    private EditText editText;

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main2);

        textView=(TextView)findViewById(R.id.textViewtest);
        editText=(EditText) findViewById(R.id.edttest);

        textView.setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View v) {
                String url = "http://192.168.43.173/jozve_howze/insert.php";
                RequestQueue queue = Volley.newRequestQueue(Main2Activity.this);
                StringRequest stringRequest=new StringRequest(Request.Method.GET, url, new Response.Listener<String>() {
                    @Override
                    public void onResponse(String response) {
                        textView.setText("sucsess");

                    }
                }, new Response.ErrorListener() {
                    @Override
                    public void onErrorResponse(VolleyError error) {
                        textView.setText("failed");

                    }
                }){
                    @Override
                    public Map<String,String> getParams(){
                        Map<String,String> params=new HashMap<>();
                        params.put("text",editText.getText().toString());
                        return  params;
                    }
                };
                queue.add(stringRequest);
            }
        });


    }
}

 اینم از کد php
...........................................................................................................................................

...........................................................................................................................................

<?php
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "test1";

$conn = new mysqli($servername, $username, $password, $dbname);

if ($conn->connect_error) {
  die("Connection failed: " . $conn->connect_error);
}
//$text=$_GET['text'];

echo '$_GET["text"]';
$sql = mysqli_query($conn,"INSERT INTO testtable (id,text)
 VALUES (0,'$_GET[text]')");
mysqli_close($conn);


?>

مشکل اینجاس اینسرت میش ولی به جای اطلاعات ستون خالیه